Asked by Raj
n
lim(n→+∞) ∑ (3/4)^k =
k=1
the n is supposed to be above the sigma sign and the k=1 is supposed to be below the sigma sign. thanks.
lim(n→+∞) ∑ (3/4)^k =
k=1
the n is supposed to be above the sigma sign and the k=1 is supposed to be below the sigma sign. thanks.
Answers
Answered by
bobpursley
http://en.wikipedia.org/wiki/Geometric_series#Sum
sum=3/4 * 1/(3/4)= 3/4*4/3=1
check that.
sum=3/4 * 1/(3/4)= 3/4*4/3=1
check that.
Answered by
Raj
could you also tell me what the series will be ?
thanks.
thanks.
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