Question
evaluate
integral of |x+1| going from -3 to 2.
i.e
2
∫ |x+1| = ?
-3
integral of |x+1| going from -3 to 2.
i.e
2
∫ |x+1| = ?
-3
Answers
drwls
Integrate x+1 from -1 to 2, and integrate -x-1 from -3 to -1.
Add the results.
[x^2/2 +x]@2 - [x^2/2 +x]@-1 = 4 + 1/2 = 9/2 That's the first part. You finish it
Add the results.
[x^2/2 +x]@2 - [x^2/2 +x]@-1 = 4 + 1/2 = 9/2 That's the first part. You finish it