Asked by anton

evaluate
integral of |x+1| going from -3 to 2.

i.e

2
∫ |x+1| = ?
-3

Answers

Answered by drwls
Integrate x+1 from -1 to 2, and integrate -x-1 from -3 to -1.

Add the results.

[x^2/2 +x]@2 - [x^2/2 +x]@-1 = 4 + 1/2 = 9/2 That's the first part. You finish it
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