Asuuming the landing ramp is at the same elevation at the takeoff ramp,
Range = (V^2)/g * sin 60 = 38.2 m
maximum height = (V sin30)^2/(2 g) = V^2/8g = 4.1 m.
You are the physics expert for a professional stuntman. The stunt you have designed includes a ramp that is angled at 30°. You expect that the stuntman will be traveling at 18.0 m/s when he leaves the ramp. How far must the landing ramp be positioned, and what is the maximum height of the flames he will be jumping over?
1 answer
1 answer