Question

How do you solve this inequality?

2x over 4 minus 5x+1 over 3 is greater than 3

Answer 1

multiply each term by 12 to get

6x - 20x - 4 > 36

It should be easy from here on, let me know what you got

Answer 2

I assume that you mean
(2x/4) - (5x+1)/3 > 3
x/2 - (5x+1)/3 > 3
Multiply both sides by 6.
3x - 10x -2 > 18
Add 2 to both sides and combine x terms.
-7x > 20
Divide both sides by -7. Multiplying by a negative number requires that the direction of > be reversed.
x < 20/7
(IF I interpreted your original inequality correctly)

Answer 3

2x/4_(5x+1)/3>3
Multiply both sides by LCM that is
(2x/4)12_[(5x+4)/3>3
Answer equals to 6x_20x_4>36
6x_20x>36+4
_14x>40
Divide both sides by_14 that is
_14x/_14>40/_14
Answer equals to x<_20/7
x<_20/7

Answer 4

I'm sorry, I made a mistake in my previous response. Let's solve it correctly this time.

We have the inequality:

2x/4 - (5x + 1)/3 > 3

We want to get rid of the fractions, so multiply both sides of the inequality by 12 (the least common multiple of 4 and 3):

12 * (2x/4) - 12 * ((5x + 1)/3) > 12 * 3

Simplifying, we get:

6x - 4(5x + 1) > 36

Distribute the -4:

6x - 20x - 4 > 36

Combine like terms:

-14x - 4 > 36

Add 4 to both sides:

-14x > 40

Now, divide both sides by -14. Remember that dividing by a negative number flips the inequality sign:

x < 40/-14

Simplifying, we get:

x < -20/7

So, the solution to the inequality is x < -20/7.