A 0.77 kg mass, attached to the end of a 0.86 m string, is whirled around in a circular horizontal path. If the maximum tension that the string can withstand is 683 N, then what maximum speed can the mass have if the string is not to break?

asked by Cassaundra

14 years ago

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1 answer

F = m v^2/r

683 = .77 v^2/.86
solve for v

answered by Damon

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Question

A 0.77 kg mass, attached to the end of a 0.86 m string, is whirled around in a circular horizontal path. If the maximum tension that the string can withstand is 683 N, then what maximum speed can the mass have if the string is not to break?

1 answer

F = m v^2/r

683 = .77 v^2/.86
solve for v

Damon · Answer

F = m v^2/r 683 = .77 v^2/.86 solve for v