Asked by Kym
a right triangle has legs of length 3x and 4x and hypotenuse of length 75. What are the lengths of the legs of the triangle.
Answers
Answered by
drwls
Yse the Pythagorean theorem to show that the hypotenuse is
5x = 75
x = 15.
Take it from there
5x = 75
x = 15.
Take it from there
Answered by
musu
Pythagorean theorem
(leg)^2 + (leg)^2= (hypoyenuse)^2
(3x)^2 + (4x)^2 =(75)^2
9x^2 +16x^2 = 5625
25x^2=5625 ]:25
x^2=225
x=15
so, first leg is 3*15=45
second leg is 4*15=60.
(leg)^2 + (leg)^2= (hypoyenuse)^2
(3x)^2 + (4x)^2 =(75)^2
9x^2 +16x^2 = 5625
25x^2=5625 ]:25
x^2=225
x=15
so, first leg is 3*15=45
second leg is 4*15=60.
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