Asked by julia
A 20.5 lb cast iron boat anchor displaces 1.33 qt of water when submerged. What is the density of the cast iron, in g/cm3?
1L=1.057 qt
1kg=2.205lb
1lb=453.6g
20.5lb X 453.6g/ 1lb = 9298.9g
1.33qt X 1L/1.057qt = 1.26L
1.26L X 1000cm3/1L = 1260cm3
9298.9g/1260cm3 = 7.38g/cm3
**now why my teacher answer is 7.39g/cm3???
1L=1.057 qt
1kg=2.205lb
1lb=453.6g
20.5lb X 453.6g/ 1lb = 9298.9g
1.33qt X 1L/1.057qt = 1.26L
1.26L X 1000cm3/1L = 1260cm3
9298.9g/1260cm3 = 7.38g/cm3
**now why my teacher answer is 7.39g/cm3???
Answers
Answered by
DrBob222
I think you rounded too soon. Just leave those numbers in the calculator.
20.5 x 453.6 = 9298.8 g (slight difference)
1.33 x 1000/1.057 = 1258.3 cc
9298.8/1248.3 = 7.39 g/cc.
20.5 x 453.6 = 9298.8 g (slight difference)
1.33 x 1000/1.057 = 1258.3 cc
9298.8/1248.3 = 7.39 g/cc.
Answered by
julia
thank you so much....your good, I wish you be my teacher I be passing my class with no problem....
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