Asked by calantha

The displacement vector for a 15.0 second interval of a jet airplane's flight is (3150, −2430) m. (a) What is the magnitude of the average velocity? (b) At what angle, measured from the positive x axis, did the airplane fly during this time interval? Express the angle as a number between −180° and +180°
Answered by bobpursley
a) magitude velocity= 1/15 * sqrt(3150^2+2430^2)

b) what is arc tan -2430/3150

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