Asked by trina

can anyone explain how to divide in algebra? I have this problem:
(15x2-24+9)/(3x-3)
I am not looking for someone to give me the answer straight out I just need to know how to get there.
Answered by Dr Russ
Start in the same way as you would do long division.

Set it up as
_________
(3x-3)|15x2-24x+9

then how many times does 3x go into 15x^2, which is 5x

5x
_________
(3x-3)|15x2-24x+9

15x2-15x (from 5x times (3x-3)


subtract

5x
_________
(3x-3)|15x2-24x+9

15x2-15x
________
-9x+9


I hope the formatting holds. Is this OK?
Answered by Dr Russ
The formatting didn't work 8-((

I hope you get the idea. I'll try again with dots for spaces.

Start in the same way as you would do long division.

Set it up as
......_________
(3x-3)|15x2-24x+9

then how many times does 3x go into 15x^2, which is 5x

.......5x
......._________
(3x-3)|15x2-24x+9

.......15x2-15x (from 5x times (3x-3)


subtract

.......5x
......._________
(3x-3)|15x2-24x+9

.......15x2-15x
............________
............-9x+9

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