Asked by Anonymous
A sample containing 1.2x10^-2 mol HCl is completely neutralized by 100.0mL of Sr(OH)2 what is the [Sr(OH)2]?
Answers
Answered by
DrBob222
Do you mean, "What is the M of the Sr(OH)2?
moles HCl = 0.012.
2HCl + Sr(OH)2 ==> SrCl2 + 2H2O
moles Sr(OH)2 = 1/2 mole HCl
[Sr(OH)2] = moles/L
moles HCl = 0.012.
2HCl + Sr(OH)2 ==> SrCl2 + 2H2O
moles Sr(OH)2 = 1/2 mole HCl
[Sr(OH)2] = moles/L
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