Asked by Carly
Customers lose their bags 8% of the time at airports.
20 random people were watched to see if their bags were lost. Whats the probability that at least 18 of them lost their bags?
20 random people were watched to see if their bags were lost. Whats the probability that at least 18 of them lost their bags?
Answers
Answered by
Reiny
at least 18 lost their bags
implies
18, 19 or 20 lost their bags.
prob of losing bag = .08
prob of not losing bag = .92
prob as stated
= C(20,18)(.08)^18 (.92)^2 + C(20,19)(.08)^19 (.92) + .08^20
= ....
you do the button-pushing
implies
18, 19 or 20 lost their bags.
prob of losing bag = .08
prob of not losing bag = .92
prob as stated
= C(20,18)(.08)^18 (.92)^2 + C(20,19)(.08)^19 (.92) + .08^20
= ....
you do the button-pushing
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