Asked by Patrick
How many grams of nitrogen monoxide gas can be produced from 80.0 ml of 4.00 M HNO3 and excess Cu?
3Cu(s)+ 8Hno3(aq)-> 3Cu(NO3)2(aq)+4H2O(/)+2NO(g)
3Cu(s)+ 8Hno3(aq)-> 3Cu(NO3)2(aq)+4H2O(/)+2NO(g)
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