Asked by David
Slove each system by substitution.
4x = y - 1
6x - 2y = -3
I have already attempted this problem and couldn't figure out what I should do.
I came out with 4x + 1 = 3x + 1.5
I think this looks right because our teacher told us that for this specific problem that we should get a decimal. But now I don't know where to go next...... Thanks!
4x = y - 1
6x - 2y = -3
I have already attempted this problem and couldn't figure out what I should do.
I came out with 4x + 1 = 3x + 1.5
I think this looks right because our teacher told us that for this specific problem that we should get a decimal. But now I don't know where to go next...... Thanks!
Answers
Answered by
TutorCat
Solve for x. Then solve for y by substitution to either of the two equations.
Answered by
David
I know but wouldn't you have to go through confusing fractions and multiply by fractions to get a whole number of x? I am trying to follow the teachers directions which do not include fractions.......
Answered by
TutorCat
multiply the entire thing by 2 to eliminate the decimal:
(4x + 1 = 3x + 1.5)*2
8x-6x=3-2
now solve for x. Then solve for y by substitution.
(4x + 1 = 3x + 1.5)*2
8x-6x=3-2
now solve for x. Then solve for y by substitution.
Answered by
David
x = 0.5
4x = 2
4(0.5) = y - 1
+1 on both sides...
y = 3!
Thanks!
4x = 2
4(0.5) = y - 1
+1 on both sides...
y = 3!
Thanks!
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