Asked by Korina
A laboratory technician is required to prepare a quarter normal saline solution (0.22% w/v) from the stock normal saline solution.
1. What is the dilution factor required?
I have 4-fold dilution - is that correct?
2. Ise this dilution factor to calculate the volume of stock needed if one litre of the diluted solution is to be prepared.
I have 0.22 over (divided by) 0.91 = 0.2417582 - is that correct? And how do I then convert it into a fraction in its lowest form?
Thanks.
1. What is the dilution factor required?
I have 4-fold dilution - is that correct?
2. Ise this dilution factor to calculate the volume of stock needed if one litre of the diluted solution is to be prepared.
I have 0.22 over (divided by) 0.91 = 0.2417582 - is that correct? And how do I then convert it into a fraction in its lowest form?
Thanks.
Answers
Answered by
DrBob222
I don't know how accurately you want this done but I would think a quarter normal solution would be 0.91/4 = 0.2275 in which case 4-fold dilution is needed.
2. I don't think it is needed.
If we use M x mL = M x mL, then
0.91/100 x mL = 0.2275/100 x 1,000
mL = 0.2275*1000/0.91 = 250. mL.
2. I don't think it is needed.
If we use M x mL = M x mL, then
0.91/100 x mL = 0.2275/100 x 1,000
mL = 0.2275*1000/0.91 = 250. mL.
Answered by
Korina
Hi DrBob222,
Thanks for your help.
:-)
Thanks for your help.
:-)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.