Asked by Cliff
Glycine is an amino acid that can be abbreviated HGly. If 27.50mL of 0.120 M NaOH neutralizes 0.248 g of HGly,what is the molar mass of the amino acid?
Answers
Answered by
bobpursley
How many moles of OH- do you have
molesOH- = .0275*.120
You need the same number of moles of HGly
molesHGly=.268/molemassHGly
solve for the molar mass of HGly.
molesOH- = .0275*.120
You need the same number of moles of HGly
molesHGly=.268/molemassHGly
solve for the molar mass of HGly.
Answered by
Dr Russ
from the abbreviated formula it is a monoprotic acid. Thus the equation for the neutralisation is
HGly + NaOH -> H2O + NaGly
so one mole of HGly reacts with one mole of NaOH.
number of moles of NaOH used is
0.02750 L x 0.120 mole L^-1
which is the same as the number of moles of HGly
so as number of moles = mass/molar mass
we can find the molar mass as mass (0.248 g) is given in the question.
HGly + NaOH -> H2O + NaGly
so one mole of HGly reacts with one mole of NaOH.
number of moles of NaOH used is
0.02750 L x 0.120 mole L^-1
which is the same as the number of moles of HGly
so as number of moles = mass/molar mass
we can find the molar mass as mass (0.248 g) is given in the question.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.