Asked by Leonardo Figueroa
You push a 250 kg desk with a force of 800N. The coefficient of friction is 0.2. What is the acceleration of the desk?
Answers
Answered by
Omer
Remember the equation: deltaF = ma
In this case delta F is the force applied(800N)-Force of friction.
Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.
u is given(.2)
N(the normal force)opposes the downward force of the desk(mg)250*9.81.
Thus Ff=.2*250*9.81=490.5
Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.
800-490.5=250a
309.5/250=a
1.24=a
theres your answer, hope i helped
In this case delta F is the force applied(800N)-Force of friction.
Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.
u is given(.2)
N(the normal force)opposes the downward force of the desk(mg)250*9.81.
Thus Ff=.2*250*9.81=490.5
Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.
800-490.5=250a
309.5/250=a
1.24=a
theres your answer, hope i helped
Answered by
drwls
Omer is correct. Thanks for helping, Omer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.