Asked by Maddy
If a weak acid has a dissociation constant of 6.4 x 10(-6), what is the pH of a solution of this acid in 0.10 molar concentration?
Answers
Answered by
DrBob222
..........HA ==> H^+ + A^-
initial...0.1....0......0
change....-x....+x......+x
final.....0.1-x...+x.....+x
Ka = (H^+)(A^-)/(HA)
Substitute into Ka expression from ICE chart above and solve for (H^+), then convert to pH.
initial...0.1....0......0
change....-x....+x......+x
final.....0.1-x...+x.....+x
Ka = (H^+)(A^-)/(HA)
Substitute into Ka expression from ICE chart above and solve for (H^+), then convert to pH.
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