Asked by Sara
translate this polar equation into a rectangular form:
rsin(2theta)=sin(theta)
My answer:
r2sin(theta)cos(theta)=sin(theta)
2rcos(theta)=1
2x=1
x=1/2
This is the only answer I can get and someone told me it's wrong. Would someone please help me with this
rsin(2theta)=sin(theta)
My answer:
r2sin(theta)cos(theta)=sin(theta)
2rcos(theta)=1
2x=1
x=1/2
This is the only answer I can get and someone told me it's wrong. Would someone please help me with this
Answers
Answered by
Sara
or maybe the answer is:
y=2xy
but that's kind of weird
y=2xy
but that's kind of weird
Answered by
Trevor
I don't know if this is right, but this is how I would work it.
rsin (2 theta) = sin (theta)
r (2 sin(theta) 2cos(theta)) = sin (theta) divide both sides by 2 sin
r 2 cos (theta) = 1/2 divide both sides by 2
r cos (theta) = 1/4
x = 1/4
rsin (2 theta) = sin (theta)
r (2 sin(theta) 2cos(theta)) = sin (theta) divide both sides by 2 sin
r 2 cos (theta) = 1/2 divide both sides by 2
r cos (theta) = 1/4
x = 1/4
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