Asked by David

1.) A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30 kg block is dropped from rest. It collides with and sticks to the spring, which is compressed 2.5 cm in bringing the block to a momentary halt. Air resistance neglible, from what height above the compressed string was the block dropped?

(Steps please?
Answered by drwls
The height from which the block was dropped, which is H above the compressed spring, satisfies the condition
gravitional P.E. lost = spring P.E. gained
M g H = (1/2) k X^2

They tell you what k, M and X are. Solve for H.
Answered by taylor
how far will 350 j raise a 7 kg mass?
There are no AI answers yet. The ability to request AI answers is coming soon!