Asked by Fred
solve. x^2 + 6x + 13 = 0
Answers
Answered by
Henry
X^2 + 6X + 13 = 0.
Complete the square:
X^2 + 6X + (6/2)^2 = -13,
X^2 + 6X + 9 = -13 + 9 = -4,
(X + 3)^2 = -4,
Take sqrt of both sides:
X + 3 = +- 2i,
X = -3 + 2i, and X = - 3 - 2i.
Complete the square:
X^2 + 6X + (6/2)^2 = -13,
X^2 + 6X + 9 = -13 + 9 = -4,
(X + 3)^2 = -4,
Take sqrt of both sides:
X + 3 = +- 2i,
X = -3 + 2i, and X = - 3 - 2i.
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