Asked by victor
a bicyclist has a mass of 50 kg. Intial velocity is 20 m/s as she hits the bottom of the hill. Doing no work, she reaches the top of the hill with a final velocity of 5 m/s. What is the vertical height of the hill?
Answers
Answered by
Damon
m g h = (1/2)mVi^2 -(1/2)m Vf^2
2 g h = Vi^2-Vf^2
h = (Vi^2-Vf^2)/(2g)
=(400 -25)/(2*9.8)
2 g h = Vi^2-Vf^2
h = (Vi^2-Vf^2)/(2g)
=(400 -25)/(2*9.8)
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