Asked by rosie
Jason takes off across level water on his jet-powered skis. The combined mass of Jason and skis is 75 kg (the mass of the fuel is negligible). The skis have a thrust of 200 N and a coefficient of kinetic friction on water of 0.1. Unfortunately, the skis run out of fuel after only 11 s. How far has Jason traveled when he finally coasts to a stop?
Answers
Answered by
drwls
While the jetski is running, the acceleration is F/m
The net thrust is F = 200-75g*0.1 = 126.5 N
Th acceleration is 126.5/75 = 1.69 m/s^2 and a maximum speed of
Vmax = 11*1.69 = 18.5 m/s is attained.
Distance travelled under power
= (1/2) at^2 = ___
Distance travelled while slowing down afterwards = (1/2)MVmax^2/(0.1 M g)
= 5 Vmax^2/g = ____
Add the two distances for the answer.
The net thrust is F = 200-75g*0.1 = 126.5 N
Th acceleration is 126.5/75 = 1.69 m/s^2 and a maximum speed of
Vmax = 11*1.69 = 18.5 m/s is attained.
Distance travelled under power
= (1/2) at^2 = ___
Distance travelled while slowing down afterwards = (1/2)MVmax^2/(0.1 M g)
= 5 Vmax^2/g = ____
Add the two distances for the answer.
Answered by
Anonymous
5400N
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