CaO + 2NH4Cl > 2NH3 + H2O + CaCl2

If 112 g of CaO and 224 g of NH4CL are mixed the theoretical yield of NH2 is 68.0 g. If only 16.3 g of NH3 is actually obtained, what is the percent yield?

User Icon for DrBob222 DrBob222 answered
13 years ago

%yield = (actual yield/theoretical yield)*100 = ??

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To calculate the percent yield, we need to compare the actual yield (16.3 g) to the theoretical yield (68.0 g) and express it as a percentage.

The percent yield formula is:

Percent Yield = (Actual Yield / Theoretical Yield) * 100

Substitute the given values into the formula:

Percent Yield = (16.3 g / 68.0 g) * 100

Calculate the value:

Percent Yield = 0.239705882 * 100

Percent Yield = 23.97%

Therefore, the percent yield is approximately 23.97%.

User Icon for Explain Bot Explain Bot answered
1 year ago

To find the percent yield, we need to compare the actual yield to the theoretical yield and calculate the percentage.

First, let's calculate the molar mass of NH3 (ammonia):
NH3: 1 atom of Nitrogen (N) + 3 atoms of Hydrogen (H) = (1 * 14.01 g/mol) + (3 * 1.01 g/mol) = 17.03 g/mol

Next, let's calculate the number of moles of NH3 based on the actual yield:
Actual yield of NH3 = 16.3 g
Number of moles of NH3 = Actual yield / Molar mass
Number of moles of NH3 = 16.3 g / 17.03 g/mol = 0.956 mol

Now, let's calculate the theoretical yield of NH3 based on the balanced chemical equation:
According to the balanced equation: 1 mol of CaO reacts with 2 mol of NH4Cl to produce 2 mol of NH3
So, the molar ratio between CaO and NH3 is 1:2.

The number of moles of CaO can be calculated as follows:
Mass of CaO = 112 g
Molar mass of CaO = 40.08 g/mol
Number of moles of CaO = Mass of CaO / Molar mass of CaO
Number of moles of CaO = 112 g / 40.08 g/mol = 2.794 mol

Using the molar ratio, the number of moles of NH3 that would be produced is:
Number of moles of NH3 = 2.794 mol of CaO * (2 mol of NH3 / 1 mol of CaO) = 5.588 mol

Now, let's calculate the theoretical yield of NH3:
Theoretical yield of NH3 = Number of moles of NH3 * Molar mass of NH3
Theoretical yield of NH3 = 5.588 mol * 17.03 g/mol = 95.08 g

Finally, we can calculate the percent yield:
Percent yield = (Actual yield / Theoretical yield) * 100
Percent yield = (16.3 g / 95.08 g) * 100 = 17.13 %

Therefore, the percent yield is approximately 17.13 %.