Asked by Tracey
                Search: a 1.0 kg mass weighs 9.8 n on earths surface and the radius of the earth is roughly 6.4x10 to the 6 m. what is the mass of the earth and the average density of Earth
            
            
        Answers
                    Answered by
            Kaitlin
            
    use the formula F=(G(m1)(m2))/r^2
G=universal gravitational constant=
6.67x10^-11 N m^2/kg^2
F=9.8 N (given)
m1=1.0 kg (given)
m2=mass of earth (variable)
r=6.4x10^6 m (given)
9.8 N=((6.67x10^-11 N m^2/kg^2)(1.0 kg)(m2))/(6.4x10^6 m)
x=6.02x10^24 kg
    
G=universal gravitational constant=
6.67x10^-11 N m^2/kg^2
F=9.8 N (given)
m1=1.0 kg (given)
m2=mass of earth (variable)
r=6.4x10^6 m (given)
9.8 N=((6.67x10^-11 N m^2/kg^2)(1.0 kg)(m2))/(6.4x10^6 m)
x=6.02x10^24 kg
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