Asked by Tracey
Search: a 1.0 kg mass weighs 9.8 n on earths surface and the radius of the earth is roughly 6.4x10 to the 6 m. what is the mass of the earth and the average density of Earth
Answers
Answered by
Kaitlin
use the formula F=(G(m1)(m2))/r^2
G=universal gravitational constant=
6.67x10^-11 N m^2/kg^2
F=9.8 N (given)
m1=1.0 kg (given)
m2=mass of earth (variable)
r=6.4x10^6 m (given)
9.8 N=((6.67x10^-11 N m^2/kg^2)(1.0 kg)(m2))/(6.4x10^6 m)
x=6.02x10^24 kg
G=universal gravitational constant=
6.67x10^-11 N m^2/kg^2
F=9.8 N (given)
m1=1.0 kg (given)
m2=mass of earth (variable)
r=6.4x10^6 m (given)
9.8 N=((6.67x10^-11 N m^2/kg^2)(1.0 kg)(m2))/(6.4x10^6 m)
x=6.02x10^24 kg
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.