Asked by Tracey
Search: a 1.0 kg mass weighs 9.8 n on earths surface and the radius of the earth is roughly 6.4x10 to the 6 m. what is the mass of the earth and the average density of Earth
Answers
Answered by
Kaitlin
use the formula F=(G(m1)(m2))/r^2
G=universal gravitational constant=
6.67x10^-11 N m^2/kg^2
F=9.8 N (given)
m1=1.0 kg (given)
m2=mass of earth (variable)
r=6.4x10^6 m (given)
9.8 N=((6.67x10^-11 N m^2/kg^2)(1.0 kg)(m2))/(6.4x10^6 m)
x=6.02x10^24 kg
G=universal gravitational constant=
6.67x10^-11 N m^2/kg^2
F=9.8 N (given)
m1=1.0 kg (given)
m2=mass of earth (variable)
r=6.4x10^6 m (given)
9.8 N=((6.67x10^-11 N m^2/kg^2)(1.0 kg)(m2))/(6.4x10^6 m)
x=6.02x10^24 kg