Question
What is the [OH-] of a saturated solution of Zn(OH)2? Ksp=1.8 x 10^-14. i'm just confused on how to start this problem i don't want the answer just the steps how to get there please
Answers
DrBob222
Zn(OH)2(s) ==> Zn^+2 + 2OH^-
Ksp = (Zn^+2)(OH^-)^2
In a saturated solution, (Zn) = x and (OH^-) = 2x
Substitute into Ksp expression and solve for x and multiply by 2 to find 2x.
Ksp = (Zn^+2)(OH^-)^2
In a saturated solution, (Zn) = x and (OH^-) = 2x
Substitute into Ksp expression and solve for x and multiply by 2 to find 2x.