Question

When a reaction mixture with a total volume of 1180 mL that is 0.0110 M aqueous NaCl was stoichiometrically produced as per the balanced equation, what volume (mL) of 0.0116 M aqueous Ca2+ was required?

3 CaCl2(aq) + 2 Na3PO4(aq) → Ca3(PO4)2(s) + 6 NaCl(aq)

Molar Mass (g)
NaCl 58.433
Ca2+ 40.078
Molar Volume (L)
22.400 at STP
Gas Constant
0.0821

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