Asked by william
how many grams of Na2CO3 must be dissolved into 155 g of water to create a solution with the molality of 8.20 mol/kg?
Answers
Answered by
Stefan A
MW(Na2CO3)=105.96g/mol
Volume- 155g H20 = 0.155L H20
Concentration- 8.20mol/L
n=CV
n=(8.20mol/L)(0.155L)
n=52.9mol
m=nMW
m=(52.9mol)(105.96g/mol)
m=5605.6g
m=5.61Kg
Volume- 155g H20 = 0.155L H20
Concentration- 8.20mol/L
n=CV
n=(8.20mol/L)(0.155L)
n=52.9mol
m=nMW
m=(52.9mol)(105.96g/mol)
m=5605.6g
m=5.61Kg
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