27x^3-8=0
(3x - 2)(x^2 + 6x + 4) = 0
x = 2/3 or x = ... (2 imaginary roots)
use the quadratic equation formula to find the 2 complex roots.
27x^3-8=0
(difference of two cubes)
1 answer
(difference of two cubes)
1 answer
2 answers
1 answer
1 answer
0 answers