A) 0.80 m/s^2 * (1.3 m + 0.80 m) / 2 = 1.04 s
B) 4 kg * 9.8 m/s^2 * (1.3 m + 0.80 m) / 2 = 39.2 m/s
C) x = (4 kg * 9.8 m/s^2 * (1.3 m + 0.80 m)^2) / (2 * 650 N/m) = 0.45 m
block a of mass 4kg is on a horizontal, frictionless tabletop and is placed against a spring of negligible mass and spring constant 650n/m. the other end of the spring is attacked to a wall. the block is pushed toward the wall until the spring has been compressed a distance x. the block is released and follows the trajectory falling 0.80m vertically and stricking a target on the floor that is a horizontal distance of 1.3 m from the edge of the table. air resistance is negligible. A). calculate the time elapsed from the instant block A leaves the table to the instant it strikes the floor. B)calculate the s of the block as it leaves the table. C)calculate the distance x the spring was ccompressed.
1 answer
1 answer