Asked by Sandi
For a scene in a movie, a stunt driver drives a 1.90 103 kg pickup truck with a length of 4.09 m around a circular curve with a radius of curvature of 0.333 km (Fig. 7.29). The truck is to curve off the road, jump across a gully 10.0 m wide, and land on the other side 2.96 m below the initial side. What is the minimum centripetal acceleration the truck must have in going around the circular curve to clear the gully and land on the other side?
Answers
Answered by
drwls
Calculate the minimum V necessary to jump across the gully. Do this by using the maximum distance it can fall while crossing the gully. That gives you a minumum allowed time to fall.
Gully width)/(max fall time)
= minumum speed
Once you have V, the centripetal acceleration is V^2/R(
Gully width)/(max fall time)
= minumum speed
Once you have V, the centripetal acceleration is V^2/R(
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