Asked by Please Help!

The premiters of two equilateral triangles are in the ratio 2:3. If the perimeter of the smaller triangle is 16 cm what is the measure of a side of the larger triangle?

Answers

Answered by MathMate
Permimeter is a linear ratio (3:2), and ratio of sides is also a linear ratio (3:2). SO if the shorter is 16, the longer one is 16*3/2=?
Answered by Please Help!
could I do it in a proportion?
Answered by MathMate
Yes, you could do it in proportion as long as both measurements are linear, e.g. perimeter and side.
Answered by Please Help!
how?
Answered by MathMate
...SO if the shorter is 16, the longer one is 16*3/2=?
Answered by Please Help!
I got 10 something but it's not one of the answers
Answered by MathMate
16*3/2 has to be greater than 16, how did you get 10?
Answered by Please Help!
3/2 = .6 repaeating x 16 = 10.6 repeating

and 16/1 x 2/3 = 10.6 reapeating
Answered by MathMate
3/2 = 3 divided by 2 = 1.5
Think of
(16*3)/2 = ?
That should make it easier!
Answered by Please Help!
But that equals 24 and that not a answer on the thing
Answered by MathMate
Sorry, I misread the question (too fast).
The perimeter of the smaller triangle is 16 cm, so the perimeter of the larger triangle should be 24 as you calculated. However, since 24 is the perimeter of three equal sides, each side should measure 24/3=8 cm.
Make sure you understand how it is to be done, or else you will get stuck on the next problem.
Answered by Please Help!
Ok I get it. Thank you!!!
Answered by MathMate
Also, it would help if you could give your first name or a pen-name of your choice so next time I would know we worked together before.
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