Asked by Brittni
                an auditorium has 50 rows of seats. THe first row has 20 seats, the row has 21 seats, the third row has 22 seats, and so on. each row having one more seat than the previous row. How many seats are there all together?
            
            
        Answers
                    Answered by
            MathMate
            
    First row = 20 seats,
second row = 21 seats,
...
nth row = 19+n seats,
...
50th row = 19+50 = 69 seats
Write the number of seats in forward and reverse order:
19 + 69 = 88
20 + 68 = 88
...
44 + 44 = 88
...
69 + 19 = 88
---------
Sum = 50*(88/2) = 2200 seats
    
second row = 21 seats,
...
nth row = 19+n seats,
...
50th row = 19+50 = 69 seats
Write the number of seats in forward and reverse order:
19 + 69 = 88
20 + 68 = 88
...
44 + 44 = 88
...
69 + 19 = 88
---------
Sum = 50*(88/2) = 2200 seats
                    Answered by
            Amber
            
    19+n
u#1=19+1
u#1=20
u#50=19+50
u#1=69
50(20+69)/2
    
u#1=19+1
u#1=20
u#50=19+50
u#1=69
50(20+69)/2
                    Answered by
            sef.Er
            
    ans.. 2225
    
                    Answered by
            Cute
            
    21×42
20×40 = 800
    
20×40 = 800
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