Question
There must be a relationship (formula) between the lengths of the sides of a Right Triangle and the angles opposite these sides.
Help Please.
Mike.
Look at the law os sines or cosines.
Law of sines
a/sin(A) = b/sin(B) = c/sin(C)
Law of cosines
a<sup>2</sup> = b<sup>2</sup> + c<sup>2</sup> - 2bc cos(A)
b<sup>2</sup> = c<sup>2</sup> + a<sup>2</sup> - 2ca cos(B)
c<sup>2</sup> = a<sup>2</sup> + b<sup>2</sup> - 2ab cos(C)
Where a, b and c are the lengths of the sides and A. B and C are the corresponding angles.
See the Pythagorean formula too
what is the maths ment to do to your brain?
Help Please.
Mike.
Look at the law os sines or cosines.
Law of sines
a/sin(A) = b/sin(B) = c/sin(C)
Law of cosines
a<sup>2</sup> = b<sup>2</sup> + c<sup>2</sup> - 2bc cos(A)
b<sup>2</sup> = c<sup>2</sup> + a<sup>2</sup> - 2ca cos(B)
c<sup>2</sup> = a<sup>2</sup> + b<sup>2</sup> - 2ab cos(C)
Where a, b and c are the lengths of the sides and A. B and C are the corresponding angles.
See the Pythagorean formula too
what is the maths ment to do to your brain?
Answers
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