Asked by Joe
If a^3 = x^2
what is a^2y+1 = x^6, solving for y
You would have
(x<sup>2</sup>)<sup>3</sup> = x<sup>6</sup> = a<sup>9</sup>
so 9 = 2y+1
Do you see why?
do u mean
a^(2y) + 1 = x^6
or
a^2 * y + 1 = x^6
a^(2y+1) = x^6
what is a^2y+1 = x^6, solving for y
You would have
(x<sup>2</sup>)<sup>3</sup> = x<sup>6</sup> = a<sup>9</sup>
so 9 = 2y+1
Do you see why?
do u mean
a^(2y) + 1 = x^6
or
a^2 * y + 1 = x^6
a^(2y+1) = x^6
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