what equation would you use if you wanted to find the net x-direction force on the box

example: here is the problem...

A box of mass 24.0 kg is subject to an applied force of 245 N with a depression angle of 31.2°, and it accelerates to the right. The horizontal surface has a coefficient of friction μ = 0.245.

What is the net x-direction force on the box?

1 answer

first find friction;

friction= mu*fnormal= mu(mg+245sinTheta)

then find the horizontal component of force fhorz= 245*cosTheta

net force= horizontal-friction