Asked by Savannah S.
What is the solubility equilibrium for Mn3(PO4)2?
Isn't it this..
Mn3(PO4)2 (s) --> 3Mn^+2 (aq) + 2PO4^-3
(aq)
but i keep getting it wrong. suggestions?
Isn't it this..
Mn3(PO4)2 (s) --> 3Mn^+2 (aq) + 2PO4^-3
(aq)
but i keep getting it wrong. suggestions?
Answers
Answered by
Savannah S.
Mn+3(PO4)+2 (s) to be exact**
Answered by
bobpursley
You wrote the solubility equation correctly (except the arrow, you should have <-->). But I suspect they want the expression to find the solubility constant, which would be
Ks= [Mn++]<sup>3</sup>[PO<sub>3</sub><sup>2</sup>]
where [] means solubility in moles/liter.
https://chemistry.twu.edu/tutorial/KspSum.html
Ks= [Mn++]<sup>3</sup>[PO<sub>3</sub><sup>2</sup>]
where [] means solubility in moles/liter.
https://chemistry.twu.edu/tutorial/KspSum.html
Answered by
Savannah S.
thank you!
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