Asked by K

I just have a couple of questions that I need some help with:

1) A 0.22-caliber handgun fires a 27g bullet at a velocity of 765m/s.

Calculate the de Broglie wavelength of the bullet.

Express your answer using two significant figures in meters.

~and~

2) An X-ray photon of wavelength 0.970nm strikes a surface. The emitted electron has a kinetic energy of 956eV.

What is the binding energy of the electron in kJ/mol?
KE=1/2mv^2; 1 electron volt (eV)=1.602*10^-19J

Answer= BEmol = _______kJ/mol

please help if possible.
Answered by Anonymous
Didn't we work a De Broglie wavelength problem for you last night? What do you think you should do or do you have an answer you would like for us to check?
Answered by Anonymous
I'm not annonymous. I don't know how that name got there.
Answered by DrBob222
I'll get it right eventually.
Answered by K
the answer came to 3.2*10^-35m. I kept typing the values into the calculator wrong. I multiplied the 765m/s, rather than dividing.

I still don't understand the other question though. Q#2.
Answered by DrBob222
#1 is ok.
#2. I assume binding energy is the same as work function.
K. E. = (hc/lambda) - work function
Convert 956 ev to Joules and substitute for K. E.
h, c, and lambda (don't forget lambda is in meters). Solve for work function.
Check my thinking. Check for typos.
Answered by K
Soooo???

KE = hc/lambda - 1.602*10^-19J*956eV??

6.6261*10^-34*3.0*10^8 / 9.7*10^-10m minus 1.53*10^-16??

=5.19*10^-17??? That can' be right??
Answered by DrBob222
I have 5.18 instead of 5.19.
Answered by K
apparently 5.18*10^-17 kJ/mol isn't the correct answer either.
Answered by K
where am I going wrong?
Answered by DrBob222
The answer 5.18 x 10^-17 is J/photon. You will need to change that to kJ/mol since the problem wants kJ/mol. Let me know if that isn't ok.
Answered by K
so just divide by 1000? I tried that when I had 5.19*10^-20 & it told me I was incorrect?
or did you mean to divide somewhere else along the way?
Answered by DrBob222
Divide by 1000 (1 kJ/1000 J) and multiply by 6.02 x 10^23 (6.02 x 10^23 photons/mol).
Answered by K
WOOO! 3.12*10^4 came to be correct indeed! Thank you ever so much for your time & patience.
Answered by DrBob222
So binding energy in your problem IS the same as work function which is the assumption I made in my first post. I've not heard it called that.
Answered by DrBob222
And thanks for letting me know.
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