Asked by Robbi
My mother in law falls from a 200m cliff. Answer the following.
a. What is her acceleration after 2 seconds? What is her acceleration after 3 sec?
b. How long will it take her to hit the ground?
c. What would be her velocity right before she hit the ground?
a. What is her acceleration after 2 seconds? What is her acceleration after 3 sec?
b. How long will it take her to hit the ground?
c. What would be her velocity right before she hit the ground?
Answers
Answered by
Ann Hiro
a) Acceleration due to gravity is a 'constant' force (generally 9.8m/s^2), so in both cases, she will be accelerating at 9.8m/s^2
b) Sorry, I don't remember the formulas, so I'm using calc for this (velocity is the integral of acceleration, position is the integral of velocity, no need for constants of integration). t = 6.388766 sec
c) v = 9.8t, so v @ 6.388766 = 62.60991 m/s
Congrats on the loss of your mother-in-law! ^_^ b
b) Sorry, I don't remember the formulas, so I'm using calc for this (velocity is the integral of acceleration, position is the integral of velocity, no need for constants of integration). t = 6.388766 sec
c) v = 9.8t, so v @ 6.388766 = 62.60991 m/s
Congrats on the loss of your mother-in-law! ^_^ b
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