I am not following protocol, I know, but this makes it MUCH easier to read. I will type the atomic number BEFORE the symbol and the mass number AFTER the symbol and as a superscript.
92U^234 --> 90Th^230 + 2He^4
The subscripts must add to the same on both sides and the superscripts must add to the same on both sides.
Note 92 protons on the left = 90+2 = 92 protons on the right.
Note 234 nucleons (protons + neutrons or mass number) on the left adds to 230 + 4 = 234 on the right.
So protons and neutrons are equal are conserved.
show that the mass number and the number of protons are conserved in the following nuclear equation:
234 230 4
92 U-----> 90 th + 2 he
1 answer