Asked by aliya
when I tried to find solution of 1/(x-3) + 1/(x-9) = 1/(x-2) + 1/ (x-8) all terms of x are cancelled out why?
Is there any rule to find solution of this?plz guide me.
Is there any rule to find solution of this?plz guide me.
Answers
Answered by
Writeacher
<b>Your school subject is Math.</b>
Answered by
MathMate
Don't know how you did to get them to cancel. Perhaps you can post your work so we can look at it.
Mean while, if you look at the function f(x), it has four vertical asymptotes at x=2,3,8,9 respectively.
It has one horizontal asymptote, y=0, evidenced by taking the limit of x in each term to ±&inf;.
You may or may not have root under these circumstances. In the particular case, there are two complex roots, which don't count in the ℝ domain.
Here's a link to the graph of the function:
http://img411.imageshack.us/img411/9915/1291291222.png
Mean while, if you look at the function f(x), it has four vertical asymptotes at x=2,3,8,9 respectively.
It has one horizontal asymptote, y=0, evidenced by taking the limit of x in each term to ±&inf;.
You may or may not have root under these circumstances. In the particular case, there are two complex roots, which don't count in the ℝ domain.
Here's a link to the graph of the function:
http://img411.imageshack.us/img411/9915/1291291222.png
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