Question
If I had the equation
H2 + I2 --> 2HI
could I write the rate of reaction as
d[H2 + I2]/dt = k[H2]^x[I2]^y
were x is the order of reaction with respect to x and y is just the order of reaction with respect to y
thanks
H2 + I2 --> 2HI
could I write the rate of reaction as
d[H2 + I2]/dt = k[H2]^x[I2]^y
were x is the order of reaction with respect to x and y is just the order of reaction with respect to y
thanks
Answers
well i guess I need the negative sense it's the reactant
-d[H2 + I2]/dt = k[H2]^x[I2]^y
is this correct?
-d[H2 + I2]/dt = k[H2]^x[I2]^y
is this correct?
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