Asked by Michael
An object has a mass of 0.3
kg. It undergoes a simple harmonic motion. The amplitude of that motion is 0.09
m and the period is 0.36 s. What is the total energy of the object?
my answer: 4.11 J
-period=1/f.
- omega=2*pi*f=17.45
only kinetic energy therefore Etotal=1/2mv^2=1/2*m*A*omega^2
=4.11 J
kg. It undergoes a simple harmonic motion. The amplitude of that motion is 0.09
m and the period is 0.36 s. What is the total energy of the object?
my answer: 4.11 J
-period=1/f.
- omega=2*pi*f=17.45
only kinetic energy therefore Etotal=1/2mv^2=1/2*m*A*omega^2
=4.11 J
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