Question

given points : p (2,1) q (-4,2) m(5,3) find the coordinates of a point n such that pq and mn are parallel find coordinate of a point k such that mk is perpendicular to pq

Answer 1

slope from p to q = (2-1)/(-4-2) = -1/6

so find n so that mn has slope of -1/6

pick any old n for n, for example x = 0
then
-1/6 = (Yn -3)/(0 - 5) = (Yn - 3) /-5
5/6 = Yn - 3
Yn = 3 5/6 = 23/6
so n (0, 23/6)

now do the same for slope = -1/(-1/6) = 6

Answer 2

hey damon i need help on mine
thank u

Answer 3

so how do i find the slope?

Answer 4

the slope of the perpendicular = -1/slope of original
m' = -1 / (-1/6) = 6

Answer 5

Oh, slope = (Y2-Y1)/(X2-X1)