Asked by Anonymous
what is the pH of an 0.155M aqueous solution of acetic acid if the Ka is 1.8 EE -5?
Answers
Answered by
DrBob222
CH3COOH ==> H^+ + H3COO^-
Ka = (H^+)(CH3COO^-)/(CH3COOH)
(H^+) = x
(CH3COO^-) = x
(CH3COOH) = 0.155-x
Solve for x and convert to pH.
Ka = (H^+)(CH3COO^-)/(CH3COOH)
(H^+) = x
(CH3COO^-) = x
(CH3COOH) = 0.155-x
Solve for x and convert to pH.
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