What is the maximum [Ba^2+] that can be maintained in 1.100 L of a 030 M solution of Na2SO4?
2 answers
Please don't change screen names. We know that you've posted a succession of chemistry questions.
BaSO4 ==> ba^+2 + SO4^-2
Ksp = (Ba^+2)(SO4^-2)
You know Ksp, substitute 0.30 M for SO4^-2 and solve for Ba^+2. That will give you moles/L and that concn will not change for different volumes. That means that concn Ba^+, in M, will be the same in 100 mL or 15 L. That's the way I've interpreted your statement. If you want to know moles, then use the molarity you calculated above and multiply by 1.1.
Ksp = (Ba^+2)(SO4^-2)
You know Ksp, substitute 0.30 M for SO4^-2 and solve for Ba^+2. That will give you moles/L and that concn will not change for different volumes. That means that concn Ba^+, in M, will be the same in 100 mL or 15 L. That's the way I've interpreted your statement. If you want to know moles, then use the molarity you calculated above and multiply by 1.1.