Asked by hannah
                Classify each of the following reactions in as many ways as possible. (Select all that apply.) 
CuO + 2 HCl --> CuCl2 + H2O
you can select:
-acid-base(unsure because there is an acid but im not sure if theres a base)
-double-displacement
-gas evolutionx
-oxidation-reduction x
-precipitation
-single-displacement x
-synthesis x
the ones i have X's on are the ones im pretty sure are not it.
            
        CuO + 2 HCl --> CuCl2 + H2O
you can select:
-acid-base(unsure because there is an acid but im not sure if theres a base)
-double-displacement
-gas evolutionx
-oxidation-reduction x
-precipitation
-single-displacement x
-synthesis x
the ones i have X's on are the ones im pretty sure are not it.
Answers
                    Answered by
            bobpursley
            
    there is NO precipate.  Metal oxides act as bases (remember definition of a base: it neutralizes acids...) Calcium oxide is a great base (quicklime).
    
                    Answered by
            hannah
            
    thanks. so would it be double displacement and acid-base?
    
                    Answered by
            bobpursley
            
    yes.
    
                    Answered by
            hannah
            
    thanks you so much. Also if i may ask im having trouble on another type of problem balancing this equation:
C5H12O(l) + O2(g) --> H2O(g) + find the compound here
I am able to balance it but i need to find the last compound i though it would be:
C5H10O2 because i took out 2 H's and 1 O. but it was wrong
    
C5H12O(l) + O2(g) --> H2O(g) + find the compound here
I am able to balance it but i need to find the last compound i though it would be:
C5H10O2 because i took out 2 H's and 1 O. but it was wrong
                    Answered by
            bobpursley
            
    the compound will be CO2
this is a combustion reaction, the products are always carbon dioxide and water.
    
this is a combustion reaction, the products are always carbon dioxide and water.
                    Answered by
            george
            
    ok i see thanks
    
                    Answered by
            hannah
            
    oops sorry
    
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