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what is the equilibrium concentration of acetate ion if the equilibrium concentration of acetic acid is .40 M, the pH is 3.85, and Ka is 1.8E-05?

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CH3COOH ==> H^+ + CH3COO^-

Ka = (H^+)(CH3COO^-)/CH3COOH)
It looks to me as if you have everything in the equation except for the one unknown. Solve for that.

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