the length of a rectangular parking lot is 3 meters less than twice its width
so
L=2W-3
and the perimeter is 408
so 2L+2W=408
you have two equations, solve for L and W
I got L=135 meters, but check the working.
so
L=2W-3
and the perimeter is 408
so 2L+2W=408
you have two equations, solve for L and W
I got L=135 meters, but check the working.
According to the problem, the length of the parking lot is 3 meters less than twice its width. This means the length is (2w - 3) meters.
The formula to calculate the perimeter of a rectangle is 2(length + width). In this case, the perimeter is given as 408 meters.
So, we can write the equation as:
2[(2w - 3) + w] = 408
Now let's solve this equation step by step to find the value of "w", which will give us the width of the parking lot.
2[2w - 3 + w] = 408
2[3w - 3] = 408
6w - 6 = 408
6w = 408 + 6
6w = 414
w = 414 / 6
w = 69
Therefore, the width of the parking lot is 69 meters.
Now, we can find the length by substituting the value of "w" into the expression (2w - 3):
Length = 2w - 3
Length = 2 * 69 - 3
Length = 138 - 3
Length = 135
Therefore, the length of the parking lot is 135 meters.