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A 100 g aluminum calorimeter contains 250 g of water. The two substances are in thermal equilibrium at 10°C. Two metallic block...Asked by Y0gi
19) A 100-g aluminum calorimeter contains 250g of water. The two substances are in thermal equilibrium at 10 C. Two metallic blocks are placed in the water. One is a 50-g piece of copper at 80 C. The other sample has a mass of 70g and is originally at a temperature of 100 C. The entire system stabilizes at a final temperature of 20 C. Determine the specific heat of the unknown second sample.
Answers
Answered by
bobpursley
What is your question on this problem?
Answered by
drwls
Heat is transferred from the two added blocks to the water and calorimeter. You can calculate that amount of heat from the increase in temperature. Set it equal to the heat lost by the two added blocks, and solve for the unknown specific heat of the second sample.
Answered by
Y0gi
so it's just Heat(cold)=Heat(hot)?
Answered by
drwls
Yes, if what you mean is
(heat gained by cold material) = (heat lost by hot material.)
(heat gained by cold material) = (heat lost by hot material.)
Answered by
Y0gi
Yes that is what I meant. Thank you, I figured it out.
Answered by
Bolaji
94.08J/kg-1oC
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