Question
A 625-kg racing car completes one lap in 14.3 s around a circular track with a radius of 50.0 m. The car moves at constant speed.
(a) What is the acceleration of the car?
(a) What is the acceleration of the car?
Answers
Your SUBJECT is not 11th grade.
yes it is
bobpursley
acceleration= V^2/r
v=PI*r*2/14.3
so acceleration= PI^2*4*r/14.3 put r in.
check my algebra.
v=PI*r*2/14.3
so acceleration= PI^2*4*r/14.3 put r in.
check my algebra.
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)^2)/r
= ((2*3.14*50/14.3)^2)/50
= 9.64 m/s^2
= (circumference/time)^2/r
= (2*pi*r/t)^2)/r
= ((2*3.14*50/14.3)^2)/50
= 9.64 m/s^2
Thank you! you are correct @carey